differentiating the clamping growth curve

If a guy’s clamped girth is X(1) and his unclamped girth is Y(1), what do you suppose is the average time (T ave) required for Y(1)=X(2) (his new unclamped girth)?

42

About as long as a piece of string.

Infinite, I hope. If Y(1) [initial unclamped] =X(2) [later clamped] then the clamped girth would have decreased, assuming Y(1) < X(1).

Did I read somewhere that you we’re getting a PhD in math?

Use this formula: T ave = sqrt(x2+y2)[a/sqrt(x2+y2) + bi/sqrt(x2+y2)]

42? No man, that’s the meaning of Life.

Ah… hmm, so… 43?

69?

This is essentially a joke, however, if T ave is infinite then clamping is not efficacious whatsoever as X(2) is defined as future unclamped girth. 69 sounds like the right answer to me. To answer your last question: yes, I’m getting a PhD in math… what can I say? - to each his own.

Wtf!?!?!?

Haven’t you people watched Jim Carey’s new movie? The number 23? EVERYTHING revolves around the number 23 ;)

Sorry, what was the question again?….

I know it’s a joke. Just taking a jab at your mistake.

Good eye. Obviously it should read X(1)=Y(2).

I guess that’s what peer-reviewing is good for :)